吳丞傑python條件判斷

from tkinter import * #或者import tkinter as tk
import math
tk = Tk()           
tk.geometry('1200x400')
tk.title("吳丞傑python tkinter三角函數")
canvas = Canvas(tk, width=1200, height=400, bg='gray')
canvas.grid(row=0,column=0,padx=5,pady=5,columnspan=3)
delay=2 # milliseconds, 1/1000秒
x1,y1,z1=0,200,10#python特徵,多變數=對等值
h=190      #上下範圍,相當於數學1到-1
def LH():
    global x1, y1, z1, inc #global全球,local當地
    if (x1 == 0): #判斷是否在左端
        inc = 1   #改成往右邊走
        canvas.delete("all")
    elif (x1 == 1200): #判斷是否在右端
        inc = -1   #改成往左邊走
        canvas.delete("all")
    x2 = x1 + inc #換到下個可能inc=1, 或inc=-1
    y2=200 - h*math.sin(0.02*x2)
    z2=200 - h*math.cos(0.02*x2)
    L1=canvas.create_line(x1,y1,x2,y2,fill='BLUE',width=10)
    L2=canvas.create_line(x1,z1,x2,z2,fill='yellow',width=10)  
    x1,y1,z1=x2,y2,z2
    canvas.after(delay,LH)
LH()            
tk.mainloop()